Nathan Aspinall vs Alex Spellman – Schedule & Where to Watch on TV

Result
5:2
09/11/2025 at 14:15 (Time Zone – GMT-5 (America/New_York))
  • Grand Slam
  • Where to Watch on TV:
czech-republicCzech-republicNova Sport 2, Oneplay
denmarkDenmarkTV3 MAX, Viaplay
finlandFinlandViaplay
germanyGermanySport 1
hungaryHungarySport 2
netherlandsNetherlandsViaplay
norwayNorwayViaplay
slovakiaSlovakiaVoyo
swedenSwedenViaplay
worldWorldPDC TV

Chances of winning


Nathan Aspinall
79.4%
Alex Spellman
20.6%

Initial Probability

(when we started the analysis)
77.1% 22.9%


Analysis of Changes in Winning Probabilities:

  • Nathan Aspinall has improved its chances compared to the initial analysis. (+2.3%)
  • Alex Spellman has seen a decrease in its chances compared to the initial analysis. (-2.3%)
  • Nathan Aspinall - Alex Spellman Odds

    1 X 2 Marga
    Avarage Now
    (Initially)
    1.17
    (1.21)

    4.36
    (4.07)
    8.4%
    (7.4%)

    • The most likely Over/Under: 7.50
    Preview Facts
    • Aspinall is ranked World Ranking: 20. Spellman is ranked World Ranking: 149.
    • Recent performances by Aspinall have been up and down (last 5 games: 3 wins).
    • In this match, Aspinall is the team to beat.
    • The players have not played against each other recently.
    Latest results of Nathan Aspinall
    Latest results of Alex Spellman
    Draw
    Play Offs

    1/8-finals
    1Humphries L. (A1)van der Velde J. (B2)10 : 3
    2Dobey C. (B1)Smith M. (A2)9 : 10
    3Woodhouse L. (C1)Evans R. (D2)9 : 10
    4Price G. (D1)Schindler M. (C2)10 : 6
    5Littler L. (E1)Nijman W. (F2)10 : 4
    6Rock J. (F1)Scutt C. (E2)10 : 9
    7van Gerwen M. (G1)Noppert D. (H2)6 : 10
    8Wenig L. (H1)Springer N. (G2)10 : 8

    Quarter-finals
    1Humphries L. (A1)Smith M. (A2)16 : 8
    2Evans R. (D2)Price G. (D1)9 : 16
    3Littler L. (E1)Rock J. (F1)16 : 12
    4Noppert D. (H2)Wenig L. (H1)16 : 8

    Semi-finals
    1Humphries L. (A1)Price G. (D1)16 : 13
    2Littler L. (E1)Noppert D. (H2)16 : 9

    Final
    1Humphries L. (A1)Littler L. (E1)11 : 16