Donna Vekic vs Diana Shnaider – Schedule & Where to Watch on TV

Tennis WTA Bad Homburg Donna Vekic - Diana Shnaider
Result
2:0
23/06/2025 at 08:00 (Time Zone – GMT-4 (America/New_York))
  • WTA - SINGLES: Bad Homburg, grass - 1/16-finals

Match Stats

Aces
51
Double Faults
11
1st Serve Percentage
53%66%
1st Serve Points Won
75% (24/32)64% (21/33)
2nd Serve Points Won
64% (18/28)47% (8/17)
Break Points Saved
100% (4/4)0% (0/3)
1st Return Points Won
36% (12/33)25% (8/32)
2nd Return Points Won
53% (9/17)36% (10/28)
Break Points Converted
100% (3/3)0% (0/4)
Service Points Won
70% (42/60)58% (29/50)
Return Points Won
42% (21/50)30% (18/60)
Total Points Won
57% (63/110)43% (47/110)
Last 10 Balls
82
Match Points Saved
00
Service Games Won
100% (9/9)67% (6/9)
Return Games Won
33% (3/9)0% (0/9)
Total Games Won
67% (12/18)33% (6/18)

Chances of winning


Donna Vekic
32.3%
Diana Shnaider
67.7%

Initial Probability

(when we started the analysis)
37.9% 62.1%

Our Initial ML Estimation

36.8% 63.2%


Analysis of Changes in Winning Probabilities:

  • Donna Vekic has seen a decrease in its chances compared to the initial analysis. (-5.6%)
  • Note: This is a significant drop in prediction, indicating that Donna Vekic's form might have worsened.
  • Diana Shnaider has improved its chances compared to the initial analysis. (+5.6%)
  • Note: This is a significant improvement in prediction, suggesting Diana Shnaider's recent form is better than expected.
  • ML Model estimates a higher probability for Donna Vekic than the current prediction. (+4.5%)
  • ML Model estimates a lower probability for Diana Shnaider than the current prediction. (-4.5%)
  • Donna Vekic - Diana Shnaider Odds

    1 X 2 Marga
    Avarage Now
    (Initially)
    2.93
    (2.51)

    1.41
    (1.53)
    5.1%
    (5.2%)
    What is the prediction for Donna Vekic - Diana Shnaider?
  • Users Predictions: 5 users predict this event. Vekic will win (votes: 1 - 20%). Shnaider will win (votes: 4 - 80%).
  • The most likely score by Bookmakers is 0:2.
  • Preview Facts
    • Vekic is ranked WTA: 22. Shnaider is ranked WTA: 12.
    • Recent form of Vekic has been disappointing (last 5 games: 1 wins).
    • Shnaider has been unpredictable lately (in the last 5 games, wins – 3).
    • Vekic may have a physical advantage due to more rest days in recent times.
    • In this match, Shnaider is seen as the favorite.
    • In the last 3 head-to-head matches, Vekic won 1 match, drew 0 matches, lost 2 matches, and goals 3:5. (average 1:1.7).
    What were the results of their latest head-to-head matches?
    The latest head-to-head matches between Donna Vekic - Diana Shnaider were as follows:
    17.06.2025 Diana Shnaider - Donna Vekic 2:0
    16.01.2025 Diana Shnaider - Donna Vekic 1:2
    29.06.2024 Diana Shnaider - Donna Vekic 2:1
    Latest results of Donna Vekic
    Latest results of Diana Shnaider
    Draw
    Singles - Main

    1/16-finals
    1Pegula J. (1)Bye
    2Kudermetova V. (LL)Siniakova K. (Q)0 : 2
    3Osaka N. (WC)Danilovic O. (Q)2 : 0
    4Kostyuk M.Navarro E. (5)0 : 2
    5Andreeva M. (3)Bye
    6Frech M.Tauson C.1 : 2
    7Tomljanovic A. (Q)Noskova L.0 : 2
    8Vekic D.Shnaider D. (6)2 : 0
    9Alexandrova E. (8)Bencic B.2 : 0
    10Putintseva Y.Sakkari M. (WC)0 : 2
    11Azarenka V. (Q)Siegemund L. (WC)2 : 0
    12ByeSwiatek I. (4)
    13Svitolina E. (7)Mertens E.2 : 0
    14Krueger A. (LL)Haddad Maia B.0 : 2
    15Fernandez L.Maria T. (WC)2 : 0
    16ByePaolini J. (2)

    1/8-finals
    1Pegula J. (1)Siniakova K.2 : 0
    2Osaka N.Navarro E. (5)0 : 2
    3Andreeva M. (3)Tauson C.2 : 1
    4Noskova L.Vekic D.2 : 1
    5Alexandrova E. (8)Sakkari M.2 : 1
    6Azarenka V.Swiatek I. (4)0 : 2
    7Svitolina E. (7)Haddad Maia B.1 : 2
    8Fernandez L.Paolini J. (2)0 : 2

    Quarter-finals
    1Pegula J. (1)Navarro E. (5)2 : 1
    2Andreeva M. (3)Noskova L.0 : 2
    3Alexandrova E. (8)Swiatek I. (4)0 : 2
    4Haddad Maia B.Paolini J. (2)0 : 2

    Semi-finals
    1Pegula J. (1)Noskova L.2 : 1
    2Swiatek I. (4)Paolini J. (2)2 : 0

    Final
    1Pegula J. (1)Swiatek I. (4)2 : 0