Result
2:1
22/06/2024 at 05:05 (Time Zone – GMT-4 (America/New_York))
- WTA - SINGLES: Bad Homburg (Germany) - Qualification, grass - Semi-finals
- Referee: Mrozinska M. (Pol)
Match Stats
| |
|---|
| Aces |
|---|
| 10 | 5 |
| Double Faults |
|---|
| 6 | 8 |
| 1st Serve Percentage |
|---|
| 58% | 52% |
| 1st Serve Points Won |
|---|
| 78% (35/45) | 63% (31/49) |
| 2nd Serve Points Won |
|---|
| 48% (16/33) | 60% (27/45) |
| Break Points Saved |
|---|
| 25% (1/4) | 56% (5/9) |
| 1st Return Points Won |
|---|
| 37% (18/49) | 22% (10/45) |
| 2nd Return Points Won |
|---|
| 40% (18/45) | 52% (17/33) |
| Break Points Converted |
|---|
| 44% (4/9) | 75% (3/4) |
| Max Points In Row |
|---|
| 5 | 7 |
| Service Points Won |
|---|
| 65% (51/78) | 62% (58/94) |
| Return Points Won |
|---|
| 38% (36/94) | 35% (27/78) |
| Total Points Won |
|---|
| 51% (87/172) | 49% (85/172) |
| Max Games In Row |
|---|
| 4 | 3 |
| Service Games Won |
|---|
| 79% (11/14) | 71% (10/14) |
| Return Games Won |
|---|
| 29% (4/14) | 21% (3/14) |
| Total Games Won |
|---|
| 54% (15/28) | 46% (13/28) |
Chances of winning
Diane Parry
55.1% | Jule Niemeier
44.9% |
Initial Probability
(when we started the analysis)
Our Initial ML Estimation
Analysis of Changes in Winning Probabilities:
Diane Parry has improved its chances compared to the initial analysis. (+5.1%)Note: This is a significant improvement in prediction, suggesting increased confidence in Diane Parry's performance.Jule Niemeier has seen a decrease in its chances compared to the initial analysis. (-5.1%)Note: This is a significant drop in prediction, and Jule Niemeier might be facing challenges that affect their performance.ML Model estimates a lower probability for Diane Parry than the current prediction. (-4.5%)ML Model estimates a higher probability for Jule Niemeier than the current prediction. (+4.5%)
Diane Parry - Jule Niemeier Odds
|
1 |
X |
2 |
Marga |
|
Avarage Now
(Initially) |
1.7 ↓
(1.85) |
|
2.09 ↑
(1.85) |
6.6%
(8.1%) | |
What is the prediction for Diane Parry - Jule Niemeier?
Users Predictions:
21 users predict this event. Parry will win (votes: 16 - 76.2%). Niemeier will win (votes: 5 - 23.8%).
Confidence interval (95%) for Parry: 58% – 94.4%. The most likely score by Bookmakers is 2:0.
Preview Facts
- Two players are playing changeable.
- Niemeier could have advantage in physics - more days for rest in last days.
- The chances to win of two players are almost the same in this match.
- Last 2 head-to-head matches Parry won 0 matches, drawn 0 matches, lost 2 matches and goals 1-4.
How many head-to-head matches has Diane Parry won against Jule Niemeier?
Diane Parry has won of their last 0 head-to-head matches.
How many head-to-head matches has Jule Niemeier won against Diane Parry?
Jule Niemeier has won of their last 0 head-to-head matches.
What were the results of their latest head-to-head matches?
The latest head-to-head matches between Diane Parry - Jule Niemeier were as follows:
Latest results of Diane Parry
Latest results of Jule Niemeier
Draw
Singles - Main1/16-finals| 1 | Pegula J. (1) | Bye | |
| 2 | Kudermetova V. (LL) | Siniakova K. (Q) | 0 : 2 |
| 3 | Osaka N. (WC) | Danilovic O. (Q) | 2 : 0 |
| 4 | Kostyuk M. | Navarro E. (5) | 0 : 2 |
| 5 | Andreeva M. (3) | Bye | |
| 6 | Frech M. | Tauson C. | 1 : 2 |
| 7 | Tomljanovic A. (Q) | Noskova L. | 0 : 2 |
| 8 | Vekic D. | Shnaider D. (6) | 2 : 0 |
| 9 | Alexandrova E. (8) | Bencic B. | 2 : 0 |
| 10 | Putintseva Y. | Sakkari M. (WC) | 0 : 2 |
| 11 | Azarenka V. (Q) | Siegemund L. (WC) | 2 : 0 |
| 12 | Bye | Swiatek I. (4) | |
| 13 | Svitolina E. (7) | Mertens E. | 2 : 0 |
| 14 | Krueger A. (LL) | Haddad Maia B. | 0 : 2 |
| 15 | Fernandez L. | Maria T. (WC) | 2 : 0 |
| 16 | Bye | Paolini J. (2) | |
1/8-finals| 1 | Pegula J. (1) | Siniakova K. | 2 : 0 |
| 2 | Osaka N. | Navarro E. (5) | 0 : 2 |
| 3 | Andreeva M. (3) | Tauson C. | 2 : 1 |
| 4 | Noskova L. | Vekic D. | 2 : 1 |
| 5 | Alexandrova E. (8) | Sakkari M. | 2 : 1 |
| 6 | Azarenka V. | Swiatek I. (4) | 0 : 2 |
| 7 | Svitolina E. (7) | Haddad Maia B. | 1 : 2 |
| 8 | Fernandez L. | Paolini J. (2) | 0 : 2 |
Quarter-finals| 1 | Pegula J. (1) | Navarro E. (5) | 2 : 1 |
| 2 | Andreeva M. (3) | Noskova L. | 0 : 2 |
| 3 | Alexandrova E. (8) | Swiatek I. (4) | 0 : 2 |
| 4 | Haddad Maia B. | Paolini J. (2) | 0 : 2 |
Semi-finals| 1 | Pegula J. (1) | Noskova L. | 2 : 1 |
| 2 | Swiatek I. (4) | Paolini J. (2) | 2 : 0 |
Final| 1 | Pegula J. (1) | Swiatek I. (4) | 2 : 0 |
