Frederico Ferreira Silva vs Maxim Zhukov – Schedule & Where to Watch on TV

Tennis Suzhou Challenger Men Frederico Ferreira Silva - Maxim Zhukov
Result
2:1
21/10/2025 at 03:00 (Time Zone – GMT-4 (America/New_York))
  • CHALLENGER MEN - SINGLES: Suzhou, hard - 1/16-finals

Match Stats

Aces
44
Double Faults
48
1st Serve Percentage
55%57%
1st Serve Points Won
71% (41/58)60% (42/70)
2nd Serve Points Won
53% (25/47)46% (24/52)
Break Points Saved
70% (7/10)73% (16/22)
1st Return Points Won
40% (28/70)29% (17/58)
2nd Return Points Won
54% (28/52)47% (22/47)
Break Points Converted
27% (6/22)30% (3/10)
Service Points Won
63% (66/105)54% (66/122)
Return Points Won
46% (56/122)37% (39/105)
Total Points Won
54% (122/227)46% (105/227)
Last 10 Balls
91
Match Points Saved
01
Service Games Won
80% (12/15)60% (9/15)
Return Games Won
40% (6/15)20% (3/15)
Total Games Won
60% (18/30)40% (12/30)

Chances of winning


Frederico Ferreira Silva
65.2%
Maxim Zhukov
34.8%

Initial Probability

(when we started the analysis)
56.9% 43.1%

Our Initial ML Estimation

59.2% 40.8%


Analysis of Changes in Winning Probabilities:

  • Frederico Ferreira Silva has improved its chances compared to the initial analysis. (+8.3%)
  • Note: This is a significant improvement in prediction, suggesting increased confidence in Frederico Ferreira Silva's performance.
  • Maxim Zhukov has seen a decrease in its chances compared to the initial analysis. (-8.3%)
  • Note: This is a significant drop in prediction, and Maxim Zhukov might be facing challenges that affect their performance.
  • ML Model estimates a lower probability for Frederico Ferreira Silva than the current prediction. (-6%)
  • Note: The ML model's lower estimate suggests that there may be underlying issues with Frederico Ferreira Silva that the model has picked up on.
  • ML Model estimates a higher probability for Maxim Zhukov than the current prediction. (+6%)
  • Note: The ML model's higher estimate suggests that Maxim Zhukov could outperform expectations, possibly based on recent matchups or player stats.
  • Frederico Ferreira Silva - Maxim Zhukov Odds

    1 X 2 Marga
    Avarage Now
    (Initially)
    1.48
    (1.6)

    2.79
    (2.11)
    3.7%
    (9.9%)
    What is the prediction for Frederico Ferreira Silva - Maxim Zhukov?
  • Users Predictions: 6 users predict this event. Ferreira Silva will win (votes: 2 - 33.3%). Zhukov will win (votes: 4 - 66.7%).
  • The most likely score by Bookmakers is 2:0.
  • Preview Facts
    • Ferreira Silva is ranked ATP: 245. Zhukov is ranked ATP: 488.
    • Both players have been playing unpredictably.
    • Zhukov may face physical challenges compared to their opponent, as they have played more matches in recent days.
    • In this match, both players are almost equally likely to win.
    • The players have not played against each other recently.
    Latest results of Maxim Zhukov
    Draw
    Singles - Main

    1/16-finals
    1Nishioka Y. (1)Zhou Y.2 : 0
    2Fomin S. (LL)Tokuda R.0 : 2
    3Ferreira Silva F.Zhukov M. (Q)2 : 1
    4Simakin I.Shimabukuro S. (RET.) (8)1 : 0
    5Rocha H. (3)Ajdukovic D. (Alt)1 : 2
    6Cui J. (RET.)Takahashi Y. (Q)1 : 1
    7Huang T. (Q)Johns G.2 : 0
    8Harris L.Kubler J. (RET.) (6)1 : 0
    9Mayot H. (5)Uchiyama Y.2 : 1
    10Mo Y. C. (WC)Honda N. (JR)0 : 2
    11Kumasaka T. (Q)Jasika O.2 : 0
    12Sun F.Shimizu Y. (9)1 : 2
    13McCabe J. (7)Jung J. (PR)2 : 1
    14Sultanov K. (Q)Wu Tung-Lin (Q)0 : 2
    15Wang A. (WC)Te R. (WC)2 : 1
    16Hsu Y. H.Wong C. (2)2 : 1

    1/8-finals
    1Nishioka Y. (1)Tokuda R.2 : 0
    2Ferreira Silva F.Simakin I.2 : 0
    3Ajdukovic D.Takahashi Y.2 : 0
    4Huang T.Harris L.1 : 2
    5Mayot H. (5)Honda N. (RET.)1 : 0
    6Kumasaka T.Shimizu Y. (9)1 : 2
    7McCabe J. (7)Wu Tung-Lin2 : 1
    8Wang A.Hsu Y. H.0 : 2

    Quarter-finals
    1Nishioka Y. (1)Ferreira Silva F.2 : 0
    2Ajdukovic D.Harris L.2 : 1
    3Mayot H. (5)Shimizu Y. (9)2 : 0
    4McCabe J. (7)Hsu Y. H.0 : 2

    Semi-finals
    1Nishioka Y. (1)Ajdukovic D.2 : 0
    2Mayot H. (5)Hsu Y. H.2 : 0

    Final
    1Nishioka Y. (1)Mayot H. (5)2 : 0