Result
2:1
30/06/2024 at 05:00 (Time Zone – GMT-4 (America/New_York))
- CHALLENGER MEN - SINGLES: Brasov (Romania) - Qualification, clay - Semi-finals
- Referee: Nicolae D. (Rou)
Match Stats
| |
|---|
| Aces |
|---|
| 12 | 0 |
| Double Faults |
|---|
| 7 | 12 |
| 1st Serve Percentage |
|---|
| 64% | 68% |
| 1st Serve Points Won |
|---|
| 82% (40/49) | 56% (44/79) |
| 2nd Serve Points Won |
|---|
| 61% (17/28) | 45% (17/38) |
| Break Points Saved |
|---|
| 75% (3/4) | 74% (17/23) |
| 1st Return Points Won |
|---|
| 44% (35/79) | 20% (10/49) |
| 2nd Return Points Won |
|---|
| 55% (21/38) | 39% (11/28) |
| Break Points Converted |
|---|
| 26% (6/23) | 25% (1/4) |
| Max Points In Row |
|---|
| 8 | 5 |
| Service Points Won |
|---|
| 74% (56/76) | 52% (61/117) |
| Return Points Won |
|---|
| 48% (56/117) | 26% (20/76) |
| Total Points Won |
|---|
| 58% (112/193) | 42% (81/193) |
| Max Games In Row |
|---|
| 4 | 3 |
| Service Games Won |
|---|
| 92% (12/13) | 57% (8/14) |
| Return Games Won |
|---|
| 43% (6/14) | 8% (1/13) |
| Total Games Won |
|---|
| 67% (18/27) | 33% (9/27) |
Chances of winning
Hynek Barton
81.7% | Mihai Alexandru Coman
18.3% |
Initial Probability
(when we started the analysis)
Analysis of Changes in Winning Probabilities:
Hynek Barton has improved its chances compared to the initial analysis. (+6.9%)Note: This is a significant improvement in prediction, suggesting increased confidence in Hynek Barton's performance.Mihai Alexandru Coman has seen a decrease in its chances compared to the initial analysis. (-6.9%)Note: This is a significant drop in prediction, and Mihai Alexandru Coman might be facing challenges that affect their performance.
Hynek Barton - Mihai Alexandru Coman Odds
|
1 |
X |
2 |
Marga |
|
Avarage Now
(Initially) |
1.14 ↓
(1.23) |
|
5.1 ↑
(3.65) |
7.2%
(8.7%) | |
Preview Facts
- The game of competitors is shaky now.
- Coman could have advantage in physics - more days for rest in last days.
- In this match Barton is a favorite.
- Recently, the players did not play each other.
How many head-to-head matches has Hynek Barton won against Mihai Alexandru Coman?
Hynek Barton has won of their last 0 head-to-head matches.
How many head-to-head matches has Mihai Alexandru Coman won against Hynek Barton?
Mihai Alexandru Coman has won of their last 0 head-to-head matches.
What were the results of their latest head-to-head matches?
The latest head-to-head matches between Hynek Barton - Mihai Alexandru Coman were as follows:
Latest results of Hynek Barton
Latest results of Mihai Alexandru Coman
Draw
Singles - Main1/16-finals| 1 | Meligeni Alves F. (1) | Maestrelli F. | 1 : 2 |
| 2 | Coppejans K. | Donski A. (Q) | 1 : 2 |
| 3 | Topo M. (Alt) | Ghetu G. (WC) | 2 : 0 |
| 4 | Gueymard Wayenburg S. | Rodriguez Taverna S. (5) | 2 : 1 |
| 5 | Compagnucci T. (LL) | Paris T. (LL) | 1 : 2 |
| 6 | Dhamne M. (WC) | Negritu Ch. | 2 : 1 |
| 7 | Feldbausch K. (NG) | Papoe R. M. (Q) | 0 : 2 |
| 8 | Albot R. (Q) | Dellien Velasco M. A. (7) | 0 : 2 |
| 9 | Martin Tiffon P. (6) | Jianu F. C. | 0 : 2 |
| 10 | Pavlovic L. | Preda L. (WC) | 2 : 0 |
| 11 | Boitan G. A. (Q) | Guerrieri A. (Q) | 2 : 0 |
| 12 | Purtseladze S. | Guillen Meza A. (4) | 1 : 2 |
| 13 | Kuzmanov D. (8) | Butvilas E. | 1 : 2 |
| 14 | Ferreira Silva F. | Soto M. | 2 : 0 |
| 15 | Mrva M. (JR) | Roca Batalla O. (Q) | 0 : 2 |
| 16 | Gakhov I. | Ficovich J. P. (2) | 0 : 2 |
1/8-finals| 1 | Maestrelli F. | Donski A. | 2 : 0 |
| 2 | Topo M. | Gueymard Wayenburg S. | 2 : 0 |
| 3 | Paris T. | Dhamne M. | 2 : 0 |
| 4 | Papoe R. M. | Dellien Velasco M. A. (7) | 2 : 0 |
| 5 | Jianu F. C. | Pavlovic L. | 0 : 2 |
| 6 | Boitan G. A. | Guillen Meza A. (4) | 2 : 0 |
| 7 | Butvilas E. | Ferreira Silva F. | 0 : 2 |
| 8 | Roca Batalla O. | Ficovich J. P. (2) | 0 : 2 |
Quarter-finals| 1 | Maestrelli F. | Topo M. | 2 : 1 |
| 2 | Paris T. | Papoe R. M. | 2 : 1 |
| 3 | Pavlovic L. | Boitan G. A. | 2 : 0 |
| 4 | Ferreira Silva F. | Ficovich J. P. (2) | 0 : 2 |
Semi-finals| 1 | Maestrelli F. | Paris T. | 2 : 0 |
| 2 | Pavlovic L. | Ficovich J. P. (2) | 2 : 0 |
Final| 1 | Maestrelli F. | Pavlovic L. | 2 : 0 |
