Result
2:0
16/02/2025 at 05:00 (Time Zone – GMT-5 (America/New_York))
- ATP - SINGLES: Doha (Qatar) - Qualification, hard - Final
Match Stats
| |
|---|
| Aces |
|---|
| 4 | 2 |
| Double Faults |
|---|
| 2 | 1 |
| 1st Serve Percentage |
|---|
| 64% | 62% |
| 1st Serve Points Won |
|---|
| 59% (26/44) | 59% (26/44) |
| 2nd Serve Points Won |
|---|
| 52% (13/25) | 48% (13/27) |
| Break Points Saved |
|---|
| 63% (5/8) | 55% (6/11) |
| 1st Return Points Won |
|---|
| 45% (20/44) | 41% (18/44) |
| 2nd Return Points Won |
|---|
| 52% (14/27) | 48% (12/25) |
| Break Points Converted |
|---|
| 45% (5/11) | 38% (3/8) |
| Winners |
|---|
| 0 | 0 |
| Unforced Errors |
|---|
| 0 | 0 |
| Net Points Won |
|---|
| 0% (0/0) | 0% (0/0) |
| Service Points Won |
|---|
| 57% (39/69) | 52% (37/71) |
| Return Points Won |
|---|
| 48% (34/71) | 43% (30/69) |
| Total Points Won |
|---|
| 52% (73/140) | 48% (67/140) |
| Last 10 Balls |
|---|
| 7 | 3 |
| Match Points Saved |
|---|
| 0 | 1 |
| Service Games Won |
|---|
| 70% (7/10) | 50% (5/10) |
| Return Games Won |
|---|
| 50% (5/10) | 30% (3/10) |
| Total Games Won |
|---|
| 60% (12/20) | 40% (8/20) |
Chances of winning
Luca Nardi
59.1% | Mikhail Kukushkin
40.9% |
Initial Probability
(when we started the analysis)
Our Initial ML Estimation
Analysis of Changes in Winning Probabilities:
Luca Nardi has seen a decrease in its chances compared to the initial analysis. (-1.6%)Mikhail Kukushkin has improved its chances compared to the initial analysis. (+1.6%)ML Model estimates a higher probability for Luca Nardi than the current prediction. (+1.1%)ML Model estimates a lower probability for Mikhail Kukushkin than the current prediction. (-1.1%)
Luca Nardi - Mikhail Kukushkin Odds
|
1 |
X |
2 |
Marga |
|
Avarage Now
(Initially) |
1.58 ↑
(1.54) |
|
2.29 ↓
(2.38) |
6.8%
(7%) | |
Preview Facts
- Nardi is ranked ATP: 83. Kukushkin is ranked ATP: 110.
- Both players are now playing unstable.
- Nardi could have advantage in physics - more days for rest in last days.
- Nardi will have a small advantage in this match.
- Recently, the players did not play each other.
How many head-to-head matches has Luca Nardi won against Mikhail Kukushkin?
Luca Nardi has won of their last 0 head-to-head matches.
How many head-to-head matches has Mikhail Kukushkin won against Luca Nardi?
Mikhail Kukushkin has won of their last 0 head-to-head matches.
What were the results of their latest head-to-head matches?
The latest head-to-head matches between Luca Nardi - Mikhail Kukushkin were as follows:
Latest results of Luca Nardi
Latest results of Mikhail Kukushkin
Draw
Singles - Main1/16-finals| 1 | Alcaraz C. (1) | Cilic M. (PR) | 2 : 0 |
| 2 | Zhang Z. | Nardi L. (Q) | 0 : 2 |
| 3 | Marozsan F. | Dougaz A. (WC) | 2 : 0 |
| 4 | Lehecka J. | Dimitrov G. (7) | 2 : 0 |
| 5 | Djokovic N. (3) | Berrettini M. | 0 : 2 |
| 6 | Struff J-L. | Griekspoor T. | 0 : 2 |
| 7 | O'Connell C. (Q) | Habib H. (WC) | 2 : 0 |
| 8 | Popyrin A. | Draper J. (8) | 0 : 2 |
| 9 | Tsitsipas S. (6) | Medjedovic H. (SE) | 1 : 2 |
| 10 | Halys Q. (Q) | Auger-Aliassime F. | 1 : 2 |
| 11 | Bergs Z. | Bautista-Agut R. | 2 : 0 |
| 12 | Khachanov K. | Medvedev D. (4) | 1 : 2 |
| 13 | Rublev A. (5) | Bublik A. | 2 : 0 |
| 14 | Virtanen O. (LL) | Borges N. | 0 : 2 |
| 15 | Van De Zandschulp B. (Q) | Shelbayh A. (WC) | 2 : 0 |
| 16 | Safiullin R. | De Minaur A. (2) | 0 : 2 |
1/8-finals| 1 | Alcaraz C. (1) | Nardi L. | 2 : 1 |
| 2 | Marozsan F. | Lehecka J. | 0 : 2 |
| 3 | Berrettini M. | Griekspoor T. | 2 : 1 |
| 4 | O'Connell C. | Draper J. (8) | 0 : 2 |
| 5 | Medjedovic H. | Auger-Aliassime F. (WO.) | |
| 6 | Bergs Z. | Medvedev D. (4) | 0 : 2 |
| 7 | Rublev A. (5) | Borges N. | 2 : 0 |
| 8 | Van De Zandschulp B. | De Minaur A. (2) | 0 : 2 |
Quarter-finals| 1 | Alcaraz C. (1) | Lehecka J. | 1 : 2 |
| 2 | Berrettini M. | Draper J. (8) | 1 : 2 |
| 3 | Auger-Aliassime F. | Medvedev D. (RET.) (4) | 1 : 0 |
| 4 | Rublev A. (5) | De Minaur A. (2) | 2 : 1 |
Semi-finals| 1 | Lehecka J. | Draper J. (8) | 1 : 2 |
| 2 | Auger-Aliassime F. | Rublev A. (5) | 1 : 2 |
Final| 1 | Draper J. (8) | Rublev A. (5) | 1 : 2 |
