Result
2:1
25/10/2024 at 04:30 (Time Zone – GMT-4 (America/New_York))
- WTA - SINGLES: Tokyo (Japan), hard - Quarter-finals
- Where to Watch on TV:
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Australia | beIN Sports 2 |
Denmark | TV2 Play |
France | beIN Sports 3 |
Germany | Sky Sport Tennis |
Greece | Nova Sports 6 |
Ukraine | Setanta Sports+ |
United-kingdom | Sky Sports Tennis |
Match Stats
| |
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Aces |
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7 | 2 |
Double Faults |
---|
3 | 6 |
1st Serve Percentage |
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56% | 61% |
1st Serve Points Won |
---|
73% (29/40) | 53% (23/43) |
2nd Serve Points Won |
---|
45% (14/31) | 46% (13/28) |
Break Points Saved |
---|
57% (4/7) | 44% (4/9) |
1st Return Points Won |
---|
47% (20/43) | 30% (12/40) |
2nd Return Points Won |
---|
54% (15/28) | 55% (17/31) |
Break Points Converted |
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56% (5/9) | 43% (3/7) |
Service Points Won |
---|
61% (43/71) | 51% (36/71) |
Return Points Won |
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49% (35/71) | 39% (28/71) |
Total Points Won |
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55% (78/142) | 45% (64/142) |
Last 10 Balls |
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5 | 5 |
Match Points Saved |
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0 | 0 |
Service Games Won |
---|
73% (8/11) | 55% (6/11) |
Return Games Won |
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45% (5/11) | 27% (3/11) |
Total Games Won |
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59% (13/22) | 41% (9/22) |
Chances of winning
Qinwen Zheng 74.3% | Leylah Annie Fernandez 25.7% |
Initial Probability
(when we started the analysis)
Analysis of Changes in Winning Probabilities:
Qinwen Zheng has seen a decrease in its chances compared to the initial analysis. (-2.1%)Leylah Annie Fernandez has improved its chances compared to the initial analysis. (+2.1%)
Qinwen Zheng - Leylah Annie Fernandez Odds
|
1 |
X |
2 |
Marga |
|
Avarage Now (Initially) |
1.28 ↑ (1.2) |
|
3.7 ↓ (3.88) |
4.9% (9.1%) | |
What is the prediction for Qinwen Zheng - Leylah Annie Fernandez?
Users Predictions:
6 users predict this event. Zheng will win (votes: 5 - 83.3%). Fernandez will win (votes: 1 - 16.7%). The most likely score by Bookmakers is 2:0.
Preview Facts
- Zheng is ranked WTA: 7. Fernandez is ranked WTA: 35.
- Zheng is in a very good shape now (in the last 5 games wins - 4).
- Fernandez is in cheap shape now (in the last 5 games wins - 1).
- Fernandez could have advantage in physics - more days for rest in last days.
- In this match Zheng is a favorite.
- Last 3 head-to-head matches Zheng won 1 matches, drawn 0 matches, lost 2 matches and goals 3:5 (average 1:1.7).
How many head-to-head matches has Qinwen Zheng won against Leylah Annie Fernandez?
Qinwen Zheng has won 1 of their last 2 head-to-head matches.
How many head-to-head matches has Leylah Annie Fernandez won against Qinwen Zheng?
Leylah Annie Fernandez has won 1 of their last 2 head-to-head matches.
What were the results of their latest head-to-head matches?
The latest head-to-head matches between Qinwen Zheng - Leylah Annie Fernandez were as follows:
10.10.2024
Qinwen Zheng
-
Leylah Annie Fernandez
2:1
14.02.2024
Qinwen Zheng
-
Leylah Annie Fernandez
0:2
Latest results of Qinwen Zheng
Latest results of Leylah Annie Fernandez
Draw
Singles - Main1/16-finals1 | Zheng Q. (1) | Bye | |
2 | Stojsavljevic M. (WC) | Uchijima M. | 1 : 2 |
3 | Gracheva V. | Hontama M. (Q) | 2 : 0 |
4 | Sasnovich A. (RET.) (LL) | Fernandez L. (8) | 1 : 1 |
5 | Shnaider D. (6) | Bye | |
6 | Tomova V. | Kudermetova V. | 2 : 0 |
7 | Saito S. (LL) | Ishii S. (Q) | 0 : 2 |
8 | Sonmez Z. (Q) | Frech M. (7) | 2 : 1 |
9 | Wang Xin. (10) | Kenin S. (WC) | 0 : 2 |
10 | Hibino N. (WC) | Tauson C. (LL) | 0 : 2 |
11 | Cocciaretto E. | Kessler M. | 0 : 2 |
12 | Bye | Kasatkina D. (3) | |
13 | Boulter K. (9) | Hon P. (Q) | 2 : 0 |
14 | Okamura K. (LL) | Baptiste H. (Q) | 2 : 0 |
15 | Andreescu B. (WC) | Yamaguchi M. (Q) | 2 : 0 |
16 | Bye | Haddad Maia B. (2) | |
1/8-finals1 | Zheng Q. (1) | Uchijima M. | 2 : 0 |
2 | Gracheva V. | Fernandez L. (8) | 1 : 2 |
3 | Shnaider D. (6) | Tomova V. | 2 : 0 |
4 | Ishii S. | Sonmez Z. | 2 : 1 |
5 | Kenin S. | Tauson C. | 2 : 1 |
6 | Kessler M. | Kasatkina D. (3) | 1 : 2 |
7 | Boulter K. (9) | Okamura K. | 2 : 0 |
8 | Andreescu B. | Haddad Maia B. (RET.) (2) | 0 : 0 |
Quarter-finals1 | Zheng Q. (1) | Fernandez L. (8) | 2 : 1 |
2 | Shnaider D. (WO.) (6) | Ishii S. | |
3 | Kenin S. | Kasatkina D. (3) | 2 : 0 |
4 | Boulter K. (9) | Andreescu B. | 2 : 0 |
Semi-finals1 | Zheng Q. (1) | Shnaider D. (6) | 2 : 0 |
2 | Kenin S. | Boulter K. (9) | 2 : 0 |
Final1 | Zheng Q. (1) | Kenin S. | 2 : 0 |