Result
2:1
16/02/2025 at 05:00 (Time Zone – GMT-5 (America/New_York))
- ATP - SINGLES: Doha (Qatar) - Qualification, hard - Final
Match Stats
| |
|---|
| Aces |
|---|
| 15 | 4 |
| Double Faults |
|---|
| 3 | 2 |
| 1st Serve Percentage |
|---|
| 61% | 52% |
| 1st Serve Points Won |
|---|
| 80% (47/59) | 82% (37/45) |
| 2nd Serve Points Won |
|---|
| 38% (14/37) | 55% (23/42) |
| Break Points Saved |
|---|
| 67% (4/6) | 50% (1/2) |
| 1st Return Points Won |
|---|
| 18% (8/45) | 22% (13/59) |
| 2nd Return Points Won |
|---|
| 45% (19/42) | 62% (23/37) |
| Break Points Converted |
|---|
| 50% (1/2) | 33% (2/6) |
| Winners |
|---|
| 0 | 0 |
| Unforced Errors |
|---|
| 0 | 0 |
| Net Points Won |
|---|
| 0% (0/0) | 0% (0/0) |
| Service Points Won |
|---|
| 64% (61/96) | 69% (59/86) |
| Return Points Won |
|---|
| 31% (27/86) | 36% (35/96) |
| Total Points Won |
|---|
| 48% (88/182) | 52% (94/182) |
| Last 10 Balls |
|---|
| 5 | 5 |
| Match Points Saved |
|---|
| 0 | 0 |
| Service Games Won |
|---|
| 86% (12/14) | 93% (13/14) |
| Return Games Won |
|---|
| 7% (1/14) | 14% (2/14) |
| Total Games Won |
|---|
| 46% (13/28) | 54% (15/28) |
Chances of winning
Quentin Halys
43.6% | Stanislas Wawrinka
56.4% |
Initial Probability
(when we started the analysis)
Our Initial ML Estimation
Analysis of Changes in Winning Probabilities:
Quentin Halys has improved its chances compared to the initial analysis. (+1.8%)Stanislas Wawrinka has seen a decrease in its chances compared to the initial analysis. (-1.8%)ML Model estimates a higher probability for Quentin Halys than the current prediction. (+0.9%)ML Model estimates a lower probability for Stanislas Wawrinka than the current prediction. (-0.9%)
Quentin Halys - Stanislas Wawrinka Odds
|
1 |
X |
2 |
Marga |
|
Avarage Now
(Initially) |
2.15 ↓
(2.28) |
|
1.66 ↑
(1.64) |
6.9%
(4.8%) | |
What is the prediction for Quentin Halys - Stanislas Wawrinka?
Users Predictions:
8 users predict this event. Halys will win (votes: 3 - 37.5%). Wawrinka will win (votes: 5 - 62.5%).
Confidence interval (95%) for Wawrinka: 29% – 96%. The most likely score by Bookmakers is 0:2.
Preview Facts
- Noskova is ranked WTA: 33. Putintseva is ranked WTA: 20.
- Two players are playing changeable.
- Putintseva could have advantage in physics - more days for rest in last days.
- Noskova will have a poor advantage in this game.
- Last 2 head-to-head matches Noskova won 1 matches, drawn 0 matches, lost 1 matches and goals 2:2 (average 1:1).
How many head-to-head matches has Quentin Halys won against Stanislas Wawrinka?
Quentin Halys has won of their last 0 head-to-head matches.
How many head-to-head matches has Stanislas Wawrinka won against Quentin Halys?
Stanislas Wawrinka has won of their last 0 head-to-head matches.
What were the results of their latest head-to-head matches?
The latest head-to-head matches between Quentin Halys - Stanislas Wawrinka were as follows:
Latest results of Quentin Halys
Latest results of Stanislas Wawrinka
Draw
Singles - Main1/16-finals| 1 | Alcaraz C. (1) | Cilic M. (PR) | 2 : 0 |
| 2 | Zhang Z. | Nardi L. (Q) | 0 : 2 |
| 3 | Marozsan F. | Dougaz A. (WC) | 2 : 0 |
| 4 | Lehecka J. | Dimitrov G. (7) | 2 : 0 |
| 5 | Djokovic N. (3) | Berrettini M. | 0 : 2 |
| 6 | Struff J-L. | Griekspoor T. | 0 : 2 |
| 7 | O'Connell C. (Q) | Habib H. (WC) | 2 : 0 |
| 8 | Popyrin A. | Draper J. (8) | 0 : 2 |
| 9 | Tsitsipas S. (6) | Medjedovic H. (SE) | 1 : 2 |
| 10 | Halys Q. (Q) | Auger-Aliassime F. | 1 : 2 |
| 11 | Bergs Z. | Bautista-Agut R. | 2 : 0 |
| 12 | Khachanov K. | Medvedev D. (4) | 1 : 2 |
| 13 | Rublev A. (5) | Bublik A. | 2 : 0 |
| 14 | Virtanen O. (LL) | Borges N. | 0 : 2 |
| 15 | Van De Zandschulp B. (Q) | Shelbayh A. (WC) | 2 : 0 |
| 16 | Safiullin R. | De Minaur A. (2) | 0 : 2 |
1/8-finals| 1 | Alcaraz C. (1) | Nardi L. | 2 : 1 |
| 2 | Marozsan F. | Lehecka J. | 0 : 2 |
| 3 | Berrettini M. | Griekspoor T. | 2 : 1 |
| 4 | O'Connell C. | Draper J. (8) | 0 : 2 |
| 5 | Medjedovic H. | Auger-Aliassime F. (WO.) | |
| 6 | Bergs Z. | Medvedev D. (4) | 0 : 2 |
| 7 | Rublev A. (5) | Borges N. | 2 : 0 |
| 8 | Van De Zandschulp B. | De Minaur A. (2) | 0 : 2 |
Quarter-finals| 1 | Alcaraz C. (1) | Lehecka J. | 1 : 2 |
| 2 | Berrettini M. | Draper J. (8) | 1 : 2 |
| 3 | Auger-Aliassime F. | Medvedev D. (RET.) (4) | 1 : 0 |
| 4 | Rublev A. (5) | De Minaur A. (2) | 2 : 1 |
Semi-finals| 1 | Lehecka J. | Draper J. (8) | 1 : 2 |
| 2 | Auger-Aliassime F. | Rublev A. (5) | 1 : 2 |
Final| 1 | Draper J. (8) | Rublev A. (5) | 1 : 2 |
