Result
7:0
10/04/2023 at 08:30 (Time Zone – GMT-4 (America/New_York))
- NETHERLANDS: TWEEDE DIVISIE - ROUND 25
Chances of winning
HHC Hardenberg 68% | Draw 18.9% | TEC 13.1% |
Initial Probability
(when we started the analysis)
Our Initial ML Estimation
Analysis of Changes in Winning Probabilities:
HHC Hardenberg has improved its chances compared to the initial analysis. (+1.6%)TEC has seen a decrease in its chances compared to the initial analysis. (-1%)ML Model estimates a higher probability for HHC Hardenberg than the current prediction. (+0.6%)ML Model estimates a higher probability for TEC than the current prediction. (+0.5%)
HHC Hardenberg - TEC Odds
|
1 |
X |
2 |
Marga |
|
Avarage Now (Initially) |
1.34 ↓ (1.36) |
4.82 ↑ (4.63) |
6.95 ↑ (6.39) |
9.8% (10.9%) | |
The most likely Over/Under: 3.25
Preview Facts
- One of the leader and one of the outsider will play in this match (ranked 3 and 15).
- Last 5 head-to-head matches HHC won 3.
- Two teams are playing changeable.
- In this match HHC is certain favorite.
- Last 8 head-to-head matches HHC won 4 matches, drawn 1 matches, lost 3 matches and goals 12-10.
- Including matches at home between the teams HHC won 2 matches, drawn 1 matches, lost 1 matches and goals 7-6.
How many head-to-head matches has HHC Hardenberg won against TEC?
HHC Hardenberg has won 1 of their last 1 head-to-head matches.
How many head-to-head matches has TEC won against HHC Hardenberg?
TEC has won 0 of their last 1 head-to-head matches.
What were the results of their latest head-to-head matches?
The latest head-to-head matches between HHC Hardenberg - TEC were as follows:
24.09.2022
TEC
-
HHC Hardenberg
0:2
Latest results of HHC Hardenberg
Draw
RelegationQuarter-finals1 | Sportlust | Scheveningen | 0 : 1, 0 : 2 |
2 | VV DOVO | Kozakken Boys | 0 : 3, 2 : 0 |
3 | Blauw Geel | Noordwijk | 1 : 4, 2 : 1 |
4 | Meerssen | Harkemase Boys | 0 : 2, 0 : 3 |
Semi-finals1 | Scheveningen | Kozakken Boys | 0 : 1, 0 : 0 |
2 | Noordwijk | Harkemase Boys | 3 : 1, 2 : 2 |
Final1 | Kozakken Boys | Noordwijk | 4 : 0, 0 : 1 |